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What is the greater of the two numbers whose product is 2560, given that the sum of the two numbers exceeds their difference by 64? |
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Answer» NONE of these Let the greater and the SMALLER NUMBER be g and s respectively. gs = 2560 g + s EXCEEDS g - s by 64 i.e., g + s - (g - s) = 64 i.e., 2s = 64 => s = 32. g = 2560/s = 80. |
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