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What is the greatest number that divides 30, 53, 99 to leave the same remainder?1. 192. 133. 214. 23 |
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Answer» Correct Answer - Option 4 : 23 Concept Used: Greatest divisor = HCF[(a – b), (b – c), (a – c)]; where a > b > c Calculation: ⇒ greatest number = HCF [(99 – 53), (99 – 30), (53 – 30)] ⇒ greatest number = HCF [46, 69, 23] = 23 ∴ Required greatest number that will divide 99, 53 and 30 so as to leave the same remainder in each case is 23 |
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