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What is the hydronium ion concentration of a 0.25 M HA solution `(K_(a)=4xx10^(-8))`A. `10^(-4)`B. `10^(-5)`C. `10^(-7)`D. `10^(-10)` |
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Answer» Correct Answer - A `underset(cong0.25)underset(0.25-x)underset(0.25)(HA)hArrunderset(x)(H^(+))+underset(x)(A^(-))` `4xx10^(-8)=(x^(2))/(0.25)` `x^(2)=4xx(25)/(100)xx10^(-8)` `x=10^(-4)` `x=[H^(+)]=10^(-4)` |
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