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What is the hypotenuse of the right triangle with perpendicular sides √2 centimetres and √3 centimetres? How much larger than the hypotenuse is the sum of the perpendicular sides? |
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Answer» Hypotenuse = \(\sqrt{\sqrt{3}^2}+\sqrt{2}^2\) \(=\sqrt{3}+2=\sqrt{5}\) cm Sum of perpendicular sides = \(\sqrt{3}+\sqrt{2}\) Difference with the hypotenuse \(=(\sqrt{3}+\sqrt{2})-\sqrt{5}\) = (1.73 + 1.41) – 2.24 = 3.14 – 2.24 cm = 0.9 |
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