What is the increase in entropy when 11.2 L of Ozare mixed with 11.2 L

1.	What is the increase in entropy when 11.2 L of Ozare mixed with 11.2 L of H, at STP?(1) 0.576 J/K (2) 5.76 J/K
Answer» Answer: 2) 5.76 J/K Explanation: STP is the temperature of 273.15 K (0 °C, 32 °F) which is ABSOLUTE pressure based on 105 Pa (100 kPa, 1 bar). S = 8.314 x 2.303 (V1 log N1 + v2 log N2) = 8.314 x 2.303 (0.5 log 0.5+0.5 log 0.5) = 8.314 x 2.303 (-0.3010) =- 5.76 Therefore, the entropy is increased by -5.76. NOTE : "-" is negligible.

What is the increase in entropy when 11.2 L of Ozare mixed with 11.2 L of H, at STP?(1) 0.576 J/K (2) 5.76 J/K

Answer»

Answer:

2) 5.76 J/K

Explanation:

STP is the temperature of 273.15 K (0 °C, 32 °F) which is ABSOLUTE pressure based on 105 Pa (100 kPa, 1 bar).

S = 8.314 x 2.303 (V1 log N1 + v2 log N2)

= 8.314 x 2.303 (0.5 log 0.5+0.5 log 0.5)

= 8.314 x 2.303 (-0.3010)

=- 5.76

Therefore, the entropy is increased by -5.76.

NOTE : "-" is negligible.