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What is the integration of log ((1- x)/ x) with limit 0 to 1? |
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Answer» The value of \(\int_0^1\) log ((1 - x) / x) dx is 0. To find the value of this we will use \(\int_0^{2a}\)f (x) dx = \(\int_0^{2a}\) f (x - 2a) dx. |
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