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What is the kinetic energy of `1 g` of `O_(2)` at `47^(@) C`?A. `3.24 xx 10^(2) J`B. `2.24 xx 10^(2) J`C. `1.24 xx 10^(2) J`D. `1.24 xx 10^(3) J`

Answer» Correct Answer - C
According to the kinetic molecular theory of gases , we have
Kinetic energy `(KE) "of n moles" = (3)/(2) nRT`
`n_(O_(2)) = ("Mass of" O_(2))/("Molar mass of" O_(2)) = (1g)/(32 g "mol"^(-1))`
`T = 47 + 273 = 230 K`
Thus ,
`KE = (3)/(2)((1)/(32) "mol") (8.314 J K^(-1) "mol"^(-1)) (320 K)`
`= 124.71 J = 1.24 xx 102 J`


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