Saved Bookmarks
| 1. |
What is the length of a simple pendulum, which ticks seconds ? |
|
Answer» SOLUTION :From Eq. (14.29), the time period of a SIMPLE pendulum is given by, `T=2pisqrt(L/g)` From this relation one gets, `L=(gT^(2))/(4pi^(2))` The time period of a simple pendulum, which ticks seconds, is 2 s. THEREFORE, for g = 9.8 m `s^(-2)` and T = 2 s, L is `=(9.8(MS^(-2))xx4(s^(2)))/(4pi^(2))` `=1M` |
|