What is the length of the pendulum of a clock which beats seconds, given that the acceleration due to gravity at the place is equal to 9.8 ms^(-2).

What is the length of the pendulum of a clock which beats seconds, giv

1.	What is the length of the pendulum of a clock which beats seconds, given that the acceleration due to gravity at the place is equal to 9.8 ms^(-2).
Answer» Solution :The period of SIMPLE PENDULUM is given by `T= 2pisqrt((l)/(G))implies` The length of the pendulum `= 1= (GT^(2))/(4pi^(2)) implies l= (9.8 xx 2^(2))/(4 xx (3.14)^(2))` `l=(9.8 xx 2^(2))/(4 xx 9.86)= 0.994 m~=1m`