1.

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth = 6400 km.)

Answer»

SOLUTION :The EARTH completes one ROTATION in 24 hour. Its | angular velocity.
`omega=(2piN)/(t)=(2pixx1)/(24xx60xx60)=(pi)/(43,200)rads^(-1)`
`R=6.4xx10^(6)` m, The linear veloctiy,
`v=Romega=6.4xx10^(6)xx(pi)/(43,200)=465.5m//s`


Discussion

No Comment Found