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What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth `=6400km`) |
Answer» The earth completes one rotation is `24 hour`. Its angular velocity. `omega=(2piN)/t=(2pixx1)/(24xx60xx60)=pi/(43,200)rad s^(-1)` The linear velocity, `v=Romega=6.4xx10^(6)xxpi/(43,000)=465.5m//s` |
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