1.

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth `=6400km`)

Answer» The earth completes one rotation is `24 hour`. Its angular velocity.
`omega=(2piN)/t=(2pixx1)/(24xx60xx60)=pi/(43,200)rad s^(-1)`
The linear velocity,
`v=Romega=6.4xx10^(6)xxpi/(43,000)=465.5m//s`


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