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What is the magnitude of force on a wire of length `0*04m` placed inside a solenoid near its centre, making an angle of `30^@` with its axis? The wire carries a current of `12A` and the magnetic field due to the solenoid is of magnitude `0*25T`.

Answer» Correct Answer - `0*06N`
Here, `l=0*04m`, `theta=30^@`, `I=12A`, `B=0*25T`.
Force, `F=IBlsin theta`
`=12xx(0*25)xx(0*04)sin 30^@`
`=12xx0*25xx0*04xx1//2=0*06N`


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