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What is the magnitude of the magnetic force per unit length on a wire carrying a current of 8 A making an angle of `30^@` with the direction of a uniform magnetic field of `0*15T`? |
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Answer» Here, `I=8A`, `theta=30^@`, `B=0*15T`, `F=?`, `l=1m`. `F=Bilsintheta=0*15xx8xx1xxsin30^@=0*15xx8xx1xx(1//2)=0*6Nm^-1` |
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