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What is the mass of a water molecule in gram ? How many molecules are present in one drop of pure water which weight 0.05 g ? If the same drop of water evaporates in one hour, calculate the number of molecules leaving the liquid surface per second.

Answer»


Solution :`"1 mol of "H_(2)O=18g=6.022xx10^(23)" molecules"`
`therefore"MASS of one molecule of "H_(2)O=(18)/(6.022xx10^(23))G=2.989xx10^(-23)g`
`0.05g" og "H_(2)O=(0.05)/(18) mol=(0.05)/(18)xx6.022xx10^(23)" molecules"=1.673xx10^(21)" molecules"`
`"No. of molecules leaving PER SEC"=(1.673xx10^(21))/(60xx60)=4.647xx10^(17)`


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