1.

What is the mass of carbon present in 0.5 moles of K_(4)[Fe(CN)_(6)] ?

Answer»


Solution :1 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 6 g atoms
0.5 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 3g atoms
MASS of carbon in grams `= (12g)xx(("3 g atoms"))/(("1G ATOM"))=36G` .


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