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What is the mass of carbon present in 0.5 moles of `K_(4)[Fe(CN)_(6)]` ? |
Answer» Correct Answer - 36 g 1 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 6 g atoms 0.5 mole of `K_(4)[Fe(CN)_(6)]` contain carbon = 3g atoms Mass of carbon in grams `= (12g)xx(("3 g atoms"))/(("1g atom"))=36g` . |
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