What is the mass of hydrogen peroxide present in 1 litre of 2M solutio

1.	What is the mass of hydrogen peroxide present in 1 litre of 2M solution? Calculate the volume of oxygen at STP liberated upon complete decomposition of 100 cm3 of the above solution.
Answer» Step 1: To calculate the mass of H₂O₂ in 1 litre of 2M solution. Molecular mass of H₂O₂ = 2 × 1 + 2 × 16 = 34 amu By definition, 1 litre of 1M H₂O₂ contains 34 g of H₂O₂ 1 litre of 2M H₂O₂ will contain H₂O₂ = 34 × 2 = 68 g Step 2 : To calculate the volume of O₂ liberated at STP from 100cm³ of 2M solution. 1 litre 2M H₂O₂ solution contains H₂O₂ = 68 g 100 cm³ of 2M H₂O₂ solution will contain \(\frac{68}{1000}\) × 100 = 6.8g of H₂O₂ The equation representing the decomposition of H₂O₂ is 2H₂O = 2 × 34 = 68g → 2H₂O + O₂ 22400cm³ at STP Now 68 g of H₂O₂ at STP give O₂ = 22400 cm³ k of O₂ 6.8 g of H₂O₂ at STP will evolve O₂ = \(\frac{22400}{68}\) x 6.8 = 2240cm³ = 2.24 mL reg

What is the mass of hydrogen peroxide present in 1 litre of 2M solution? Calculate the volume of oxygen at STP liberated upon complete decomposition of 100 cm3 of the above solution.

Answer»

Step 1: To calculate the mass of H₂O₂ in 1 litre of 2M solution.

Molecular mass of H₂O₂ = 2 × 1 + 2 × 16 = 34 amu

By definition, 1 litre of 1M H₂O₂ contains 34 g of H₂O₂

1 litre of 2M H₂O₂ will contain H₂O₂ = 34 × 2 = 68 g

Step 2 : To calculate the volume of O₂ liberated at STP from 100cm³ of 2M solution.

1 litre 2M H₂O₂ solution contains H₂O₂ = 68 g

100 cm³ of 2M H₂O₂ solution will contain \(\frac{68}{1000}\) × 100 = 6.8g of H₂O₂

The equation representing the decomposition of H₂O₂ is

2H₂O = 2 × 34 = 68g → 2H₂O + O₂ 22400cm³ at STP

Now 68 g of H₂O₂ at STP give O₂ = 22400 cm³ k of O₂

6.8 g of H₂O₂ at STP will evolve O₂ = \(\frac{22400}{68}\) x 6.8 = 2240cm³ = 2.24 mL reg

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