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What is the mass of precipitate formed when 15mL of 16.9% solution of AgNO3 is mixed with 50mL of 5.8% NaCl solution? a.7g b. 14g c. 28g d. 3.5g |
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Answer» Answer: 7g Explanation: AgNO3+NaCl→AGCL+NaNO3 ForAgNO3, V=50ml V/W%=16.9% W/50=16.9/100 WAgNO3=8.45g nAgNO3=WAgNO3/MAgNO3 =0.05 ForNaCl, V=50ml W/V%=5.8%WNaCl=2.9g nNaCl=WNaCl/MNaCl =0.05 According to REACTION AgCl(ppt) = 0.05 moles × Molar MASS of AgCl = 0.05 × 142.8 = 7.14g ≈ 7g |
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