1.

What is the mass of the goods that must be put on the piston so that the volume of the gas becomes halved?

Answer»

56 kg
80 kg
110 kg
92 kg

Solution :P'V' =PV
`RARR P = 2P=8 xx 10^5 = P_0 +(MG+MG)/(S_0)`
`7xx 10^5 xx 20 xx 10 ^-4 - 600 = Mg`
`rArrM = 80 kg`


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