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What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide ? For iron sulphide, K_(sp)=6.3xx10^(-18). |
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Answer» Solution :Suppose the CONCENTRATION of each of `FeSO_(4) and Na_(2)S ` is xmol `L^(-1)` . Then after mixing equal volumes, `[FeSO_(4)]=[Na_(2)S]=(x)/(2) M, i.e., [Fe^(2+)]=[S^(2-)]=(x)/(2)M` `F_(sp) "for" =[Fe^(2+)][S^(2-)] , i.e., 6.3xx10^(-18) = (x)/(2)xx(x)/(2)orx^(2) = 25.2 xx 10^(-18), or x =5.02xx10^(-9)M`. |
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