1.

What is the maximum number of electron possible in `Ni^(+)` having same spin.

Answer» Correct Answer - [0015]
`[Ni^(+) = 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(7)`
Maximum number of electron having same spin `= 15]`


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