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What is the maximum number of spectral line emitted by a hydrogen atom when it is in the third excited state ? |
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Answer» If n is the quantum number of highest energy level, then the total number of possible spectral line emitted is N = n(n - 1) / 2 Here third excited state means fourth energy level, i.e.n = 4 N = 4(4 - 1) / 2 = 6 |
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