1.

What is the maximum speed with which a cylist can turn around curved path of radius 10.0 m, if the coefficient of friction between the tyre and the road is 0.5 ? If the cyclist wants to avoid overturning by what angle the cyclist must lean from the vertical ?

Answer»

Solution :Radius = r=10.0 m
MU = 0.5`
MAXIMUM speed `=V= sqrt(murg) = sqrt(0.5 xx 10.0 xx 9.8) = 7`m/s
For no overturning, `tan theta = v^(2)/(rg) = (murg)/(rg) = mu = 0.5`
`therefore = 26.8^(@)`


Discussion

No Comment Found