1.

What is the maximumvolumeof waterrequired to dissolve1 g of calciumsulphate at298 K . For calciumsulphate K_(sp) = 9.1 10^(-5)

Answer»

Solution :`CaSO_(4) (aq) hArr CA^(2+)(aq) +SO_(4)^(2-) (aq)`
If S ISTHE solubilityof `CaSO_(4)` in moles `L^(-1)`
`K_(sp) = [Ca^(2+)] = [SO_(4)^(2-)] = S^(2)`
` :. S = sqrt(K_(sp)) = sqrt(9.1 xx10^(-6))`
` = 3.02 xx10^(-3) "ML"^(-1)` .
` = 3.02 xx10^(-3) xx136 "gmL"^(-1)`
` = 0.411 "gL"^(-1)`
For dissolving `1gCaSO_(4)`water required = `1/(0.41) L = 2.431 `


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