What is the mid point of the line joining points (2, 4) and (- 2, 8)?1

1.	What is the mid point of the line joining points (2, 4) and (- 2, 8)?1. (2, 6)2. (0, 4)3. (0, 6)4. (2, 8)
Answer» Correct Answer - Option 3 : (0, 6) Concept: If we consider point A (x₁, y₁) and B (x₂, y₂) then Mid-point of AB = (x, y) can be given by \(\left( {x,\;y} \right) = \frac{{ x_1 ~+ ~x_2}}{2},\frac{{y_1 ~+~ y_2}}{2}\) Calculate: Given: We have A (2, 4) and B(- 2, 8). If we consider point A (x1, y1) and B (x2, y2) then Mid-point of AB = (x, y) can be given by \(\left( {x,\;y} \right) = \frac{{ x_1~ +~ x_2}}{2},\frac{{y_1 ~+~ y_2}}{2}\) \(\left( {x,\;y} \right) = \frac{{ 2~+~(-2)}}{2},\frac{{4~+~8}}{2}\) (x, y) = (0, 6)

What is the mid point of the line joining points (2, 4) and (- 2, 8)?1. (2, 6)2. (0, 4)3. (0, 6)4. (2, 8)

Answer» Correct Answer - Option 3 : (0, 6)

Concept:

If we consider point A (x₁, y₁) and B (x₂, y₂)

then Mid-point of AB = (x, y) can be given by

\(\left( {x,\;y} \right) = \frac{{ x_1 ~+ ~x_2}}{2},\frac{{y_1 ~+~ y_2}}{2}\)

Calculate:

Given:

We have A (2, 4) and B(- 2, 8).

If we consider point A (x1, y1) and B (x2, y2)

then Mid-point of AB = (x, y) can be given by

\(\left( {x,\;y} \right) = \frac{{ x_1~ +~ x_2}}{2},\frac{{y_1 ~+~ y_2}}{2}\)

\(\left( {x,\;y} \right) = \frac{{ 2~+~(-2)}}{2},\frac{{4~+~8}}{2}\)

(x, y) = (0, 6)

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