What Is The Minimum Number Of Nodes In An Avl Tree Of Height H?

1.	What Is The Minimum Number Of Nodes In An Avl Tree Of Height H?
Answer» The minimum number of nodes S(H), in an AVL tree of HEIGHT h is given by S(h)=S(h-1)+S(h-2)+1. For h=0, S(h)=1. The minimum number of nodes S(h), in an AVL tree of height h is given by S(h)=S(h-1)+S(h-2)+1. For h=0, S(h)=1.

Answer»

The minimum number of nodes S(H), in an AVL tree of HEIGHT h is given by S(h)=S(h-1)+S(h-2)+1. For h=0, S(h)=1.

The minimum number of nodes S(h), in an AVL tree of height h is given by S(h)=S(h-1)+S(h-2)+1. For h=0, S(h)=1.

Discussion