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What is the minimum pH required to prevent the precepitation of ZnS in a solution that is 0.01 M ZnCl_(2) and saturated with 0.10 M H_(2)S? [Given k_(sp) " of " ZnS = 10^(-21), "For " H_(2)S K_(a1) xx K_(a2) = 10^(-20)]

Answer»


Solution :`K_(SP) =[ZN^(2+)][S^(2-)]`
`[S^(2)] =10^(-21)/0.01 = 10^(-19)`
`THEREFORE` for `K_(a1).K_(a2) = ([H^(+)]^(2)[S^(2-)])/([H_(2)S])`
`10^(-20) = ([H^(-)]^(2) xx 10^(-19))/(0.1) rArr [H^(+)] = 0.1` or pH =1


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