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What is the minimum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M ZnCl_2 and saturated with 0.10 M H_2S? Given K_(sp) of ZnS=10^(-21) , for H_2S K_(a_1)xK_(a_2)=10^(-20)

Answer»


SOLUTION :`K_(sp)=[ZN^(2+)][S^(-2)]`
:. [5^2]=10^(-21)/10.01=10^(-19)`
`K_(a_1)xxK_(a_2)=([H^+]^(2)[10^(-19)])/0.1implies 10^(-20)=([H^+]^(2)[10^(-19)])/0.1`
`[H^+]=10^(-1)`
pH=1


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