1.

What is the minimum thickness of a soap film needed for constructive interference in reflected light, if the light incident on the film is 750 nm? Assume that the refractive index for the film is µ = 1.33.(a) 282 nm (b) 70.5 nm (c) 141 nm (d) 387 nm

Answer»

(c) 141 nm

Explanation: Here, 2µt = \(\frac{λ}{2}\)

∴ tmin = \(\frac{λ}{4\mu}=\frac{750}{4\times1.33}\) = 141 nm



Discussion

No Comment Found

Related InterviewSolutions