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What is the minimum thickness of a soap film needed for constructive interference in reflected light, if the light incident on the film is 750 nm? Assume that the refractive index for the film is µ = 1.33.(a) 282 nm (b) 70.5 nm (c) 141 nm (d) 387 nm |
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Answer» (c) 141 nm Explanation: Here, 2µt = \(\frac{λ}{2}\) ∴ tmin = \(\frac{λ}{4\mu}=\frac{750}{4\times1.33}\) = 141 nm |
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