What is the minimum volume of water required to dissove 1g of calcium sulphate at 298K ? (For calcium sulphate, K_(sp) is 9.1xx10^(-6)).

What is the minimum volume of water required to dissove 1g of calcium

1.	What is the minimum volume of water required to dissove 1g of calcium sulphate at 298K ? (For calcium sulphate, K_(sp) is 9.1xx10^(-6)).
Answer» Solution :Solubility product of calcium sulphate, `K_(sp)` for `CaSO_4 = 9.1 XX 10^(-6)` Solubility of `CaSO_4= SQRT(K_(sp))= 3.016 xx 10^(-3)mol L^(-1)` Solubility of `CaSO_4 = 3.016 xx 10^(-3)xx136 = 0.41 g L^(-1)` 0.41 gram of `CaSO_4` is dissolved in a solution of VOLUME one litre. Volume of solution in which 1 gram of `CaSO_4` is dissolved `=" weight " xx (1)/("solubility ")=1 xx (1)/(0.41 ) = 2.441` .