1.

What is the molality of a solution containing 200 mg of urea (molar mass = 60 g mol^(-1)) ?

Answer»

0.0825
0.825
0.498
0.0014

SOLUTION :No. of moles of UREA `= (0.2g)/(("60 G mol"^(-1)))=0.0022` mol
Mass of water in kg `=(40)/(1000)=0.04kg`
Molality of solution `= (("0.0033 mol"))/(("0.04 kg"))`
`= 0.0825 "mol Kg"^(-1)=0.0825`m .


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