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What is the molality of a solution containing 200 mg of urea (molar mass = 60 g mol^(-1)) ? |
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Answer» 0.0825 Mass of water in kg `=(40)/(1000)=0.04kg` Molality of solution `= (("0.0033 mol"))/(("0.04 kg"))` `= 0.0825 "mol Kg"^(-1)=0.0825`m . |
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