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What is the molality of a solution formed when 58.5g of NaCl is dissolved in 2000 mL of water?(a) 29.2500 m(b) 0.5000 m(c) 0.0005 m(d) 0.2925 mThe question was posed to me during an online interview.Question is from Expressing Concentration of Solutions in division Solutions of Chemistry – Class 12

Answer»

Correct option is (b) 0.5000 m

For explanation: Given,

Mass of NaCl, m = 58.5 g

MOLES of NaCl, n = mass/molar mass

n = 58.5g/(58.5 g/mole) = 1 mole

Molality = moles of solute/mass of solvent (in kg)

Volume of solvent = 2000 ml = 2 L

Mass of solvent = volume X density = 2 L x 1 kg/L = 2 kg

Molality = 1 mole/2 kg = 0.5 molal.



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