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What is the molality of a solution which contains 36g of glucose in 250g of water?

Answer» Sahi h Royal Thakur ...
Given,Mass of solute, glucose = 36 gMass of solvent, water = 250 gMolar mass of glucose = 180 g/moleMolality\xa0: It is defined as the number of moles of solute present in the one kilogram of solvent.Formula used :where,\xa0= mass of solute, glucose\xa0= mass of solvent, water\xa0= molar mass of solute, glucoseNow put all the given values in the above formula, we getTherefore, the molality of solution is, 0.8 mole/Kg


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