What is the molar solubility of Fe(OH)_2 (K_(sp) =8.0 xx 10^(-16) )at

1.	What is the molar solubility of Fe(OH)_2 (K_(sp) =8.0 xx 10^(-16) )at pH 13.0 ?
Answer» `8.0 xx 10^(-18) ` ` 8.0 xx 10^(-15)` ` 8.0 xx 10^(-17) ` ` 8.0 xx 10^(-14)` Solution :` FE( OH)_2 hArr Fe^(+2) +2OH^(-) ` ` "" S "" (2S +0.1 ) ` ` 8 xx 10 ^(-16)=(S) ( CANCEL (2S) +0.1 ) ^(2) ` ` S= 8 xx 10 ^(-14)M`

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