What is the molar solubility product for V3(PO4)5 in terms of KSP?(a) S = (KSP/84375)^1/8(b) S = KSP^1/8(c) S = (KSP/15)^1/8(d) S = (KSP/108)^1/8I had been asked this question during an online interview.I need to ask this question from Solubility Solutions in chapter Solutions of Chemistry – Class 12

What is the molar solubility product for V3(PO4)5 in terms of KSP?(a)

1.	What is the molar solubility product for V3(PO4)5 in terms of KSP?(a) S = (KSP/84375)^1/8(b) S = KSP^1/8(c) S = (KSP/15)^1/8(d) S = (KSP/108)^1/8I had been asked this question during an online interview.I need to ask this question from Solubility Solutions in chapter Solutions of Chemistry – Class 12
Answer» Right option is (a) S = (KSP/84375)^1/8 To explain: The dissociation reaction is represented as V3(PO4)5 → 3V^5+ + 5PO4^3- If S is the SOLUBILITY of V^5+ and PO4^3- ions then KSP = [3V^5+]^3 [5PO4^3-]^5, where the SQUARE BRACKETS indicate the molar concentrations of the ions in the SOLUTION. KSP can then be written as KSP = [3S] ^3[5S] ^5 = 3^3 x 5^5 x S^8 gives KSP=84375 x S^8. Therefore, on rearranging, S = (KSP/84375)^1/8.

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