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What is the molarity of a 15 ml, 2 M aqueous solution when 285 ml of water is added to it?(a) 0.400 M(b) 0.100 M(c) 0.111 M(d) 0.105 MI have been asked this question in examination.My query is from Expressing Concentration of Solutions topic in section Solutions of Chemistry – Class 12

Answer» RIGHT option is (b) 0.100 M

For explanation: Given,

Initial concentration, M1 = 2 M

Initial TOTAL volume, V1 = 15 ml

Final total volume, V2 = 15 + 285 = 300 ml

Final concentration, M2 = to be found

Before and after adding WATER number of moles of solute remain constant SINCE it does not react with water.

Number of moles = concentration x volume

Thus, M1 x V1 = M2 x V2

On substituting, M2 = (2 x 15)/300 = 0.1 M.


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