1.

What is the molarity of H_(2)SO_(4) solution if 25 ml of exactly neutralised with 32.63 ml of 0.164M, NaoH

Answer»

0.107 M
0.126 M
0.214 M
`-0.428M`

SOLUTION :0.164 M NAOH`-=`0.164 N NaOH
We know, `N_(1)V_(1)=N_(2)V_(2),N_(1)xx25=0.164xx32.63`
0.214N `H_(2)SO_(4)-=(0.214)/(2)"M "H_(2)SO_(4)`(`because"BASICITY of "H_(2)SO_(4)` is 2)
`-=0.107" M "H_(2)SO_(4)`


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