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What is the mole fraction of glycerin C3H5(OH)3 in a solution containing 33g of glycerin, 60g isopropyl alcohol and rest water?(a) 0.359(b) 0.258(c) 0.205(d) 0.480This question was addressed to me in class test.This interesting question is from Expressing Concentration of Solutions topic in section Solutions of Chemistry – Class 12

Answer»

Correct choice is (c) 0.205

Best explanation: Mw of glycerin = 92g/mol. Number of moles of glycerin = 33/92 = 0.3587 mol

Number of moles of isopropyl ALCOHOL = 60G/(60g/mole) = 1 mole

Number of moles of WATER = 7g/(18g/mole) = 0.3889 mole

Mole fraction of glycerin = 0.3587/(0.3587 + 1 + 0.3889) = 0.205.



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