1.

What is the mole fraction of NaCl, when solution is prepared by dissolving 5.85 gram NaCl in 90 gram of water ?

Answer»

`0.2`
`0.1`
`0.01`
`0.0196`

SOLUTION :`X_(NACL)=(5.85//58.5)/((90)/(18)+(5.85)/(58.5))`
`= (0.1)/(5.1)`
= 0.0196.


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