1.

What is the mole fraction of the solute in a 1.00 m aqueous solution?

Answer»

0.0354
0.0177
0.177
1.77

SOLUTION :1.0 m aqueous solution means 1 MOLE of the solute is present in 1000 G of water
`"1000 g of "H_(2)O=(1000)/(18)" moles = 55.5 moles"`
i.e., `n_(H_(2)O)=55.5`
Mole fraction,
`x_("solute")=(n_("solute"))/(n_("solute")+n_(H_(2)O))=(1)/(1+55.5)=0.0177`


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