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What is the mole fraction of the solute in a 1.00m aqueous solution ? |
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Answer» 0.0354 `n_(H_2O)=1000/18` = 55.5 mol `H_2O` `X_"solute"=n_"solute"/(n_"solute" + n_(H_2O))` `=1/(1+55.5)`=0.0177 |
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