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What is the mole fraction of the urea in 2.5 m aqueous solution ? |
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Answer» 2.5 m means , 2.5 moles of urea present in 1000 g of solvent.... No.of moles of urea= 2.5/60=1/24=0.041... No.of moles of water= 1000/18=55.5......Therefore, Mole fraction= 0.041/0.041+55.5=0.041/55.541=0.0007... Ans Maybe 0.043 |
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