What is the moment of inertia of a ring about a tangent to the circle

1.	What is the moment of inertia of a ring about a tangent to the circle of the ring?
Answer» <html><body><p></p>Solution :The tangent to the ring in the plane of the ring is <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> to one of the <a href="https://interviewquestions.tuteehub.com/tag/diameters-950922" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETERS">DIAMETERS</a> of the ring. <br/> The <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between these two parallel axes is R, the radius of the ring. Using the parallel axes theorem, <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BEN_PHY_XI_P1_C07_SLV_012_S01.png" width="80%"/> <br/> `I_("tangent")=I_(dia)+MR^(2)=(MR^(2))/(2)+MR^(2)=(3)/(2)MR^(2)`.</body></html>

What is the moment of inertia of a ring about a tangent to the circle of the ring?