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What is the moment of inertia of a rod of mass M, length l about an axis perpendicular to it through one end? |
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Answer» Solution :For the rod of mass M and length L, `I = Ml^(2)//12`. Using the parallel axes theorem, `I ′ = I + Ma^(2)` with`a = l//2`we GET, `I.=M(l^(2))/(12)+M((l)/(2))^(2)=(Ml^(2))/(3)` We can check this INDEPENDENTLY since I is HALF the moment of INERTIA of a rod of mass 2M and length 2l about its midpoint, `I.=2M.(4l^(2))/(12)xx(1)/(2)=(Ml^(2))/(3)` |
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