1.

What is the moment of inertia of a rod of mass M, length l about an axis perpendicular to it through one end?

Answer»

Solution :For the rod of mass M and length L, `I = Ml^(2)//12`. Using the parallel axes theorem, `I ′ = I + Ma^(2)` with`a = l//2`we GET,
`I.=M(l^(2))/(12)+M((l)/(2))^(2)=(Ml^(2))/(3)`
We can check this INDEPENDENTLY since I is HALF the moment of INERTIA of a rod of mass 2M and length 2l about its midpoint,
`I.=2M.(4l^(2))/(12)xx(1)/(2)=(Ml^(2))/(3)`


Discussion

No Comment Found