What is the net gain in a Krebs cycle ?A. `1 FADH_(2), 2 NADH_(2) "and " 1 ATP`B. `2 FADH_(2), 2 NADH_(2) "and " 2 ATP`C. `1 FADH_(2), 3 NADH_(2) " and " 1 ATP`D. `1 FADH_(2), 6 NADH_(2) " and " 2 ATP`

What is the net gain in a Krebs cycle ?A. `1 FADH_(2), 2 NADH_(2) "and

1.	What is the net gain in a Krebs cycle ?A. `1 FADH_(2), 2 NADH_(2) "and " 1 ATP`B. `2 FADH_(2), 2 NADH_(2) "and " 2 ATP`C. `1 FADH_(2), 3 NADH_(2) " and " 1 ATP`D. `1 FADH_(2), 6 NADH_(2) " and " 2 ATP`
Answer» Correct Answer - C

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Find out the values of x, y and z in the given equation : `2(C_(51)H_(98)O_(6))+xO_(2)rarryCO_(2)+zH_(2)O+` EnergyA. x- 102, y- 145, z- 98B. x- 145, y- 102, z- 98C. x- 98, y- 102, z- 145D. x- 145, y- 98, z- 102
Refer the given equation. `2(C_(51)H_(98)O_(6)) + 145O_(2) rarr 102CO_(2) +98H_(2)O +` Energy The RQ in this case isA. 1B. 0.7C. 1.45D. 1.62
Refer the given equation. `2(C_(51)H_(98)O_(6)) + 145O_(2) rarr 102CO_(2) +98H_(2)O +` Energy The RQ in this case isA. 1B. 0.7C. 1.45D. 1.62.
Refer the given equation. `2(C_(51)H_(98)O_(6)) + 145O_(2) rarr 102CO_(2) +98H_(2)O +` Energy The RQ in this case isA. 0·7B. `oo` (infinity)C. 1·45D. 1·62
In glycolysis, glucose splits into compounds which areA. 5-CB. 4-CC. 2-CD. 3-C
Make corrections wherever you find mistake in spellings/words in the following paragraphs :- A. When fats are used in respiration, the RQ is more than unity because fats contain more `O_(2)` and require relatively less amount of `O_(2)` for oxidation. B. The most important energy carrier is ATP. This energy rich compound is mobile and can pass from one cell into another. C. Before pyruvic acid enters Krebs cycle, one of the two carbon atoms of pyruvic acid is reduced to carbon dioxide in the reaction called reductive carboxylation. The remaining two carbon pyruvate unit is accepted by coenzyme A to form acetyl coenzyme A.
Respiratory quotient of which diet is less than unity ?A. CarbohydrateB. FatsC. Organic acidD. Sugar
Which of the following is the product of glucose fermentation by yeast ?A. `C_(6)H_(12)O_(6)`B. `C_(2)H_(5)OH`C. `(C_(6)H_(10)O5)_(n)`D. `CH_(2)OH`
Which of the molecule listed below is a product of fermentation of glycose by yeast?A. `(C_(6)H_(10)O_(5))_(n)`B. `C_(2)H_(5)OH`C. `C_(6)H_(12)O_(6)`D. `CH_(3)OH`
Respiratory quotient may be represented asA. Volume of `CO_(2)` evolved = volume of `O_(2)` consumedB. (Volume of `O_(2)` consumed)/(Volume of `CO_(2)` evolved)C. (Volume of `CO_(2)` evolved)/(Volume of `O_(2)` consumed)D. (Volume of `O_(2)` evolved)/(Volume of `CO_(2)` consumed)

What is the net gain in a Krebs cycle ?A. `1 FADH_(2), 2 NADH_(2) "and " 1 ATP`B. `2 FADH_(2), 2 NADH_(2) "and " 2 ATP`C. `1 FADH_(2), 3 NADH_(2) " and " 1 ATP`D. `1 FADH_(2), 6 NADH_(2) " and " 2 ATP`

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