1.

What is the number of atoms present in 32 g of oxygen gas and 14 g of nitrogen gas?

Answer»

Gram atomic mass of oxygen is 16 g
So, 16 g oxygen contains 6.023 × 1023 atoms
Hence 32 g oxygen will contain 6.023 × 1023 × 2 atoms
=12.046 x 1023
Now, gram atomic mass of Nitrogen = 14 g
So, 14 g nitrogen contains 6.023 × 1023 atoms



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