What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solution if density of sulfuric acid is 1.83 g/cm^3?(a) 63.7(b) 11.9(c) 6.5(d) 11.6I got this question during an interview.Question is from Expressing Concentration of Solutions in section Solutions of Chemistry – Class 12

What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solut

1.	What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solution if density of sulfuric acid is 1.83 g/cm^3?(a) 63.7(b) 11.9(c) 6.5(d) 11.6I got this question during an interview.Question is from Expressing Concentration of Solutions in section Solutions of Chemistry – Class 12
Answer» Correct option is (b) 11.9 Easy explanation: 98% (v/v) means 98 mL of acid is present in 100 mL of solution. In 650 mL of solution, volume of acid present = 0.98 x 650 mL = 637 mL Mass of acid present = volume x density = 637 mL x 1.83 g/mL =1165.71 g Molar mass of sulfuric acid (H2SO4) = (2 x 1 + 32 + 4 x 16) = 98 g/mole Number of MOLES of sulfuric acid = mass/molar mass = 1165.71g/(98 g/mole) = 11.9 moles.

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What is the number of moles in 650 mL of 98% (v/v) sulfuric acid solution if density of sulfuric acid is 1.83 g/cm^3?(a) 63.7(b) 11.9(c) 6.5(d) 11.6I got this question during an interview.Question is from Expressing Concentration of Solutions in section Solutions of Chemistry – Class 12

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