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What is the number of photons of light with a wavelength of 4000pm that provide 1 J of energy?Plz help me with correct and complete solution! Physical science question |
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Answer» 2.012 * 10^16 Explanation: ENERGY of one photon (E) = hv Energy of ‘n’ photons (En) = nhv => n = Enλ/hc Where λ is the wavelength of the photons: = 4000 pm = 4000 * 10^-12 meter c denotes the speed of light in vacuum = 3 * 10^8 m/sec h is plancks constant whose value = 6.26 * 10^-34 J/sec Substituting these values in the expression for n: n = 1 * 4000 * 10^-12 /( 6.26 * 10^-34)(3*10^5) = 2.012 * 10^16 Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are 2.012 * 10^16. |
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