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What , is the numberof photonsof ligthwith awavelengthof 400pm thatprovide1 j ofenergy |
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Answer» Solution :Wavelength`(LAMBDA)= 400 pm:. , 1 pm = 10^(12) m` Energy(E ) = 1J If numberof photon =N energyof Nphoton= `(Nhc )/(lambda ) = E` `N = (E xx lambda )/( hc )` `=(11xx 4000 xx 10^(12)m)/( 6.626 xx 10^(34) j s xx3.0xx 10^(8) MS^(-1))` 2.012 `xx10^(16)`number ofphoton |
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