1.

What is the orbital angularmomentum forelectronin 2sorbital ?

Answer»

`(1)/(2) .(H)/(2PI)`
Zero
`(h)/(2pi)`
`SQRT(2).(h)/(2pi)`

Solution :Orbitalangularmomentum`=sqrt(l(1+1)).(h)/(2pi)`
for`2s l=0= sqrt(0(0+1)) .(h)/(2pi)=0`
(for2 s orbital l=0)


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